Euclide Geometry Principles


ΔABC right triangle in C Define r its inradius, a=BC,b=AC and c=A PCRO is square => PC=CR=r AC et AB tangents to the circle=>AP=AQ, BQ=BR and CP=CR b=AC=AP+PC, a=BC=BR+RC AC+BC=b+a=AP+r+BR+r=2r+AP+BR AP=AQ, BR=BQ => AC+BC=b+a=2r+AQ+BQ=2r+AB=2r+c a+b=2r+c Therefore r=(a+b-c)/2 Define p as the semi-perimeter of the triangle, p=(a+b+c)/2 Therefore r =p-c

Inradius in right triangle







AG and AH are tangent to a circle with center O =>AG=AH Proof AG and AH are tangent to a circle with center O <=>∠AHO=∠AGO= π/2 OH=OG=r => O is at the same distance of AH and AG => O in on the angle bissector of ΔGAH => ∠GAO=∠HAO =>ΔOAG […]

Tangents to a circle




From Gogeometry Using : Isometric transformation Additional points congruent triangles Area of a triangle Define a square ABCD Define E in AB, AE=a and EB=b Define F in BC such as BF=b and FC=a [ABCD]=[HIGD]+[EBFI]+[AEIH]+[FCGI] [AEIH]=[FCGI]=ab=>[ABCD]=a^2+b^2+2ab=(a+b)^2 Cut [AEIH] in 2 triangles T1=AEI and T2=AHI Cut [FCGI] in 2 triangles T3=FCG […]

Pythagoras theorem