From Gogeometry
Using
- Additional points
- Inscribed angles in a circle
- central and inscribed angle
- congruent triangles
- Concyclic points
∠ABC=∠ADC = π/2 => ABCD are concyclic with center O
=> OA=OD=OC=OB
Define D’ such as ΔCAD is congruent to ΔCAD’
∠CDA=∠CD’A = π/2 =>D’ is on the circle O
=> ∠ACD= ∠ACD’= α => ∠BCD’= α
=>ΔECD is congruent to ΔECD’ (SAS) => ED=ED’
∠ACD= ∠ACD’= ∠BCD’= α => ∠AOD= ∠AOD’= ∠BOD’= 2α
∠DOD’= ∠AOB= 4α =>ΔDOD’ is congruent to ΔAOB (SAS)
=> DD’=AB
DD’=2DE
Therefore AB=2 DE