Gogeometry Problem 244

 dans Euclide Geometry Problem par Harvey Littleman

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From Gogeometry :

 

Using :

• isometric transformation
• additional point
• Pythagoras

• Define H such as ΔHOB is the rotation of ΔMOC of -Π
• => OM ⊥ OH, OM=OH=a, MC ⊥ HB
• MC ⊥ ME, MC ⊥ HB => ME // HB
• Hence MEBH is a parallelogram
• => HM=BE=b
• => b is the hypothenuse of a rectangle triangle with side=a
• Therefore 2a^2=b^2

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