From Gogeometry


Using
- Pythagoras
 - congruent triangles
 - Similar triangles
 - Equilateral triangle
 - Area of a triangle
 - Tangents to a circle
 - Inradius in right triangle
 

•Pythagoras on triangle ΔBFC => (1) BF^2+CF^2=BC^2=a^2 
•Incircle in a right triangle => (2) 2x=BF+CF-BC =BF+CF-a 
•[ABCD]= 4 triangles areas + square with side 2x => (3) S=a^2=2BF.CF+4x^2 
•(1 & 3) BF^2+CF^2=a^2=2BF.CF+4x^2 
•BF^2+CF^2-2BF.CF=4x^2 •(CF-BF)^2=4x^2 => (4) CF-BF=2x 
•(2 & 4) : 2x=BF+CF-a=CF-BF => (5) 2BF=a 
•=> BF=a/2 and  BF ⊥ CF => ΔBFC is half of an equilateral triangle 
•=> (6) CF=a√3/2 •(4 & 5 & 6) CF-BF=2x= a√3/2 – a/2 
•=>x=(√3-1)a/4